Question

Search this book n, in this case, reads Pi = Pf | M2V2,i = mjº18+ m2V2,f. ergy reads K; = K mavzi = {m101s+ mauz.s. lons in two unknowns. The algebra is tedious but not terribly difficult; you de (mi-m2)+1,i+2m2 U2, mi + m2 (m2-mi U2,+2m, V1, mi +m2 U2f numbers, we obtain V1,8 V2,1 = = 2.22 m -0.28 m

Solve for v1 and v2 given conservation of kinetic energy

Answer 1

mv2, mysf mvf -1 Divide D (Vzi-V2t) H2i-43 2) V2,i+ V2f = Vi7f D

me (vrii-,f) = Vi, f m1 V2,4 V2fV1,f m2 vi,i-V2i Ml N2(m-m) m2tm1 and V2, (mm)v2Vit
in your answer v1 ' = 0 , which is equal to my answer ( from equation 4 and 5 )