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A parachutist whose mass is 65 kg drops from a helicopter hovering 1500 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b 20 N-sec/m when the chute is closed and b2 90 N-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 25 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec2 The parachutist will reach the ground after□ seconds. Round to two decimal places as needed.)

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K 31.88 845 6189.447 -0.000003구 t 0.000003구구 | e ん 2.183-3.99t (*)- x (4.835)10.61I m 085 45 562-10.69 7.085 timatakam 15-18 asplease rate it up thanks :)

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