An air-filled parallel plate capacitor with a plate spacing of 1.20 cm has a capacitance of...
An air-filled parallel plate capacitor with a plate spacing of 1.90 cm has a capacitance of 4.10 μF. The plate spacing is now doubled and a dielectric is inserted, completely filling the space between the plates. As a result the capacitance becomes 16.9 μF. Calculate the dielectric constant of the inserted material.
Show work please An air-filled parallel-plate capacitor has a capacitance of 1 pF. The plate separation is then doubled and a wax dielectric is inserted, completely filling the space between the plates. As a result, the capacitance becomes 2 pF. What is the dielectric constant of the wax? 0.25 0 50 2.0 4.0 8.0 A 60-watt light bulb carries a current of 0.5 ampere. The total charge passing through it in one day is what? 36.200 C 43.200 C 24.200...
An air-filled parallel-plate capacitor has a capacitance of 1.2 pF. The separation of the plates is doubled and wax is inserted between them. The new capacitance is 1.8 pF. Find the dielectric constant of the wax.
An air-filled parallel-plate capacitor has a capacitance of 1.4 pF. The separation of the plates is doubled and wax is inserted between them. The new capacitance is 2.1 pF. Find the dielectric constant of the wax.
An air-filled capacitor is made from two flat parallel plates 1.4 mm apart. The inside area of each plate is 8.8 cm2. a) What is the capacitance of this set of plates (in pF) b) If the region between the plates is filled with a material whose dielectric constant is 6.6, what is the new capacitance (in pF)? 2) A parallel-plate capacitor with only air between its plates is charged by connecting the capacitor to a battery. The capacitor is...
Chapter 25, Problem 040 An air-filled parallel-plate capacitor has a capacitance of 1.6 pF. The separation of the plates is doubled and wax is inserted between them. The new capacitance is 4.3 pF. Find the dielectric constant of the wax. Number the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work Units
A parallel-plate capacitor filled with air carries a charge Q. The battery is disconnected, and a slab of material with dielectric constant k = 2 is inserted between the plates. Which of the following statements is correct? The voltage across the capacitor decreases by a factor of 2. The voltage across the capacitor is doubled. The electric field is doubled. The charge on the plates decreases by a factor of 2. The charge on the plates is doubled.
A parallel-plate capacitor with only air between the plates is charged by connecting it to a battery. The capacitor is then disconnected from the battery, without any of the charge leaving the plates. A. A voltmeter reads 44.0 V when placed across the capacitor. When a dielectric is inserted between the plates, completely filling the space, the voltmeter reads 11.0 V . What is the dielectric constant of this material? B. What will the voltmeter read if the dielectric is...
A parallel-plate capacitor has charge of magnitude 8.40 µC on each plate and capacitance 3.60 µF when there is air between the plates. The plates are separated by 2.10 mm. With the charge on the plates kept constant, a dielectric withκ = 6is inserted between the plates, completely filling the volume between the plates. (Enter the magnitudes.)(a)What is the potential difference between the plates of the capacitor (in V) before and after the dielectric has been inserted?before Vafter V(b)What is...
(1 point) A parallel plate capacitor is filled with a dielectric that has a dielectric constant of 1.09. The plates have an area of 2.26 mm² and are separated by a distance of 2.86 um. (A) What is the capacitance of this filled capacitor? (B) What is the capcitance of this capacitor when it is empty? (C) If the filled capacitor is connected to a 9 volt battery, what is the charge stored on the plates of this filled capacitor?...