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in a sample of 900 US adults, 173 dine out at a restaurant more than once...

in a sample of 900 US adults, 173 dine out at a restaurant more than once per week. two US adults are selected at random from the population of all US adults without replacement.   assuming the sample is representative of all US adults, complete parts (a) through (d).
(a) find the probability that both adults dine out more than once per week.

the probability that both adults dine out more than once per week is????
round to three decimal places as needed.

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Answer #1

As given in uestis the sample, = 900 umber mehe than onee es peaple ho dline out at mestaurrant w2 meek. = 173 we aue to find oust he prehabi blts oline aut mase than once lity that Step T Brohability f selecting an aduit usho dine aut more epeA, 10 eek = 173 900 Also given in guestin, the selection ㅆ den e koithaut eplacement. So, ater ist step, the sample sgebe 839 ad the nuurbes t adults alive eut maze than ence - 1구2. Step IT probability at aut mese Phan Once . st step of electing an adult who dine per week = 132 899fcem shep1 step IL nat both me steps are independat each othes. So he psbabilty at hoth adults dine aut mare Once per week :

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