Two charges are located on the x axis as shown in the figure, d # 1.18...

Question

Question

Answer 1

Answer #1

here,

d = 1.18 cm = 0.0118 m

q1 = 11.1 uC = 11.1 * 10^-6 C

q2 = - 18.3 uC = - 18.3 * 10^-6 C

the electric feild at origin , E = - K * q1 /d^2 + K * q2 /(2d)^2 + K * q3 /(3d)^2

as the net electric feild is zero at origin

0 = - K * q1 /d^2 + K * q2 /(2d)^2 + K * q3 /(3d)^2

0 = - q1 /1^2 + q2 /(2)^2 + q3 /(3)^2

0 = - 11.1 * 10^-6 /1^2 + 18.3 * 10^-6 /(2)^2 + q3 /(3)^2

solving for q3

q3 = - 5.87 *10^-5 C = - 58.7 uC

the charge q3 is - 58.7 uC

Answer 2

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