1) d) because force is no longer a restoring force at an angle
2) Time period = 2pi*sqrt(L/g)
time period depends on length and acceleration due to gravity and not on mass
so both will have same period
so option c) is the correct answer
3)
Please give correct answers ï. When a pendulum swings with a small angle its motion is...
A simple pendulum has a rod of length LL with a bob of mass
m=0.100 kg at the end of the rod. The rod is supposed to be very
light and all the mass is imagined to be concentrated in the
bob.
A) What is the tension in the string when the pendulum swings by
an angle θ=5.00∘?
B) What is the magnitude of the restoring force on the bob when
θ=5.00∘?
C) If you drop a perpendicular from the...
Please answer with the correct amount of significant
figures. Thank you!!
A simple pendulum has a mass of 0.650 kg and a length of 7.00 m. It is displaced through an angle of 8.0° and then released. Using the analysis model of a particle in simple harmonic motion, calculate the following. (Give your answer to the thousandths place.) (a) What is the maximum speed of the bob? m/s 4.0 (b) What is the maximum angular acceleration of the bob? |...
Hi, please provide the correct answer ASAP. circle the answers
clearly. This is the 2nd time I've had to ask this so plz. come
through.
much appreciated,
Thanks!
-/12.5 POINTS EXAMPLE 13.1 Simple Harmonic Motion on a Frictionless Surface GOAL Calculate forces and accelerations for a horizontal spring system. PROBLEM A 0.350-kg object attached to a spring of force constant 1.30 x 10- N/m is free to move on a frictionless horizontal surface. If the object is released from rest...
I need all of these answers please!!!!!! Will give good
rating.
7. -11 points SerCP11 13.P032 My Notes Ask Your Teacher A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 8.40 N is applied. A 0.440-kg particle rests on a frictionless horizontal surface and is attached to the free end of the spring. The particle is displaced from the origin to x = 5.00 cm and released from rest at t = 0,...
please answer all prelab questions, 1-4.
This is the prelab manual, just in case you need background
information to answer the questions. The prelab questions are in
the 3rd photo.
this where we put in the answers, just to give you an
idea.
Lab Manual Lab 9: Simple Harmonic Oscillation Before the lab, read the theory in Sections 1-3 and answer questions on Pre-lab Submit your Pre-lab at the beginning of the lab. During the lab, read Section 4 and...
please give me answers to all the questions and i would really
appreciate that
thank you
6. -0 points My Notes O Ask Your Teache A 10.1 kg object oscillates at the end of a vertical spring that has a spring constant of 2.20 x 104 N/m. The effect of air resistance is represented by the damping coefficient b = 3.00 N-s/m (a) Calculate the frequency of the dampened oscillation. H2 (b) By what percentage does the amplitude of the...
Please do not answer unless you are sure it is correct. thank
you.
" A mass hanging from a vertical spring is somewhat more complicated than a mass attached to a horizontal spring because the gravitational force acts along the direction of motion. Therefore, the restoring force of the oscillations is not provided by the spring force alone, but by the net force resulting from both the spring force and the gravitational force. Ultimately, however, the physical quantities of motion...
Review Constants Let's begin with a straightforward example of simple harmonic motion (SHM). A spring is mounted horizontally on an air track as in (Figure 1), with the left end held stationary. We attach a spring balance to the free end of the spring, pull toward the right, and measure the elongation. We determine that the stretching force is proportional to the displacement and that a force of 60 N causes an elongation of 0.030 m. We remove the spring...
Now measure the distance, x,
for two more masses and enter your measurements in the table below.
Try to estimate to the nearest 0.5 mm. Find the spring constant by
solving mg = kx for k. The spring constant is a property of the
spring so you should get nearly the same result each time.
Part 1: Spring Constant Background: A spring scale works because it obeys Hooke's Law: F=-kx. When you hang a weight, the spring stretches until the...