here,
mass , m = 80 kg
a)
the speed of quaterback just after releasing the ball , v = 8.1 * 10^-2 m/s
b)
the time taken by quaterback in air , t = 0.3 s
so the distance travelled by quaterback at constant speed , d = v * t
d = 2.43 * 10^-2 m
To practice Problem-Solving Strategy 11.1 for conservation of momentum problems. An 80-kg quarterback jumps straight up...
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An 80- quarterback jumps straight up in the air right before throwing a 0.43- football horizontally at 15. How fast will he be moving backward just after releasing the ball?Suppose that the quarterback takes 0.30 to return to the ground after throwing the ball. How far will he move horizontally, assuming his speed is constant?Which interaction will you analyze in this problem? The quarterback jumping off of the ground. The quarterback throwing the ball. The ball encountering air resistance after being thrown. The quarterback...
An 80kg quarterback jumps straight up in the air right before throwing a 0.43kg football horizontally at 15m/s . How fast will he be moving backward just after releasing the ball? (THIS IS NOT THE QUESTION THAT IS TO BE ANSWERED) This is the question (THAT NEEDS TO BE ANSWERED): Which of the following best describes why you can analyze this event using conservation of momentum? a. The throwing action is quick enough that external forces may be ignored. b....
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