Oxygenated hemoglobin absorbs weakly in the red (hence its red color) and strongly in the near infrared, whereas deoxygenated hemoglobin has the opposite absorption. This fact is used in a "pulse oximeter" to measure oxygen saturation in arterial blood. The device clips onto the end of a person's finger and has two light-emitting diodes—a red (653 nm) and an infrared (906 nm)—and a photocell that detects the amount of light transmitted through the finger at each wavelength.
(a) Determine the frequency of each of these light sources.
red | Hz |
infrared | Hz |
(b) If 62% of the energy of the red source is absorbed in the
blood, by what factor does the amplitude of the electromagnetic
wave change? Hint: The intensity of the wave is equal to
the average power per unit area as given by I
=
Emax2 |
2μ0c |
=
c |
2μ0 |
Bmax2.
Oxygenated hemoglobin absorbs weakly in the red (hence its red color) and strongly in the near...
A "pulse oximeter operates by using light and a photocell to measure oxygen saturation in arterial blood. The transmission of light energy as it passes through a solution of light-absorbing molecules is described by the Beer-Lambert law which gives the decrease in intensity I in terms of the distance L the light has traveled through a fluid with a concentration C of the light-absorbing molecule. The quantity ε is called the extinction coefficient, and its value depends on the frequency of...
> For part b, subtract your percentage by 1 then square root it. So for this problem it would be (1-0.62) = 0.38, then sqrt(0.38) = 0.62
mochi12 Sat, Mar 5, 2022 1:32 PM