Question

2.) A spring hangs vertically from the ceiling. Its natural length is 1.0 m. When a mass of 2.0 kg is attached to the spring, the spring's equilibrium length is 1.5 m. (a.) What is the spring constant k? The mass displaced vertically from equilibrium by 1.0 cm. (b.) What is the period of oscillation? (c.) What is the maximum speed of the mass? (d.) Suppose I wanted to maximize the oscillation amplitude by tapping on the mass. At what frequency should I tap? After the mass comes to rest, it is displaced horizontally by 1.0 cm. (e.) What is the period of oscillation?

Answer 1

@ (a) ke - may 25 15-4 = 0.5m 2 = 1.5-1 = 0.5m. k(0.5) = 2x9.8 k = 39.2 I (6) Period of Period oscillation - Taorm oscillation = T = 21 T = 212 39.2 = 1.42 see maximam Vomax = speed = Aw {1x10-2m) = 4.43x10 - 2 m/dee frequenz of block - 4 = 0.705 H3 So we should top of 0.705 H2. 0 T = 2T 7 = 25 [15 T = 21 - = 2.46 see 2.46 9.8 see

T Sinzoo Fy 30° TEG 30° 0 {Fx = 0 {fy = 0 - Fx = 766300 = T3 - Fy t T sinzo - ma Fy = mg - I - © (a) &r =0 obou hinge - mgg & Trin 30xd = T = my o. ② Fy=0 from ean For = mg 53 so force by kinge = mg 53