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When a solid dissolves in water, heat may be evolved or absorbed. The heat of dissolution (dissolving) can be determined usin
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Answer #1

We can use the following formula

Q = mc∆T

Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat (units J/g∙oC), is a symbol meaning "the change in"

∆T = change in temperature (oC Celcius)

Heat released by BaBr2 = Heat gained calorimeter + Heat gained by water

Heat gained by calorimeter = (25.93 oC- 22.79oC) x 1.77 J/oC = 5.5578 oC

Heat gained by water = 102.4 gm x 4.184 J/g∙oC x (25.93 oC- 22.79oC) = 1345.3066 Joules

Heat relased by BaBr2 = 5.5578 oC  +  1345.3066 Joules =  1,350.8644‬ Joules = 1.35 Kilo Joules

Moles of BaBr2 =  297.14 g/mol

Moels of BaBr2 = 19.35 gm / 297.14 g/mol = 0.06512 Moles

Enthalpy of dissolution of BaBr2 =  1.35 Kilo Joules / 0.06512 Moles = 20.73 Kilo Joules

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