The concept used to solve this question is to draw the and forms of glucose.
Haworth projection is the method of representing monosaccharides in a cyclic ring.
Similarly, glucose is a monosaccharide and can be represented as Haworth projection.
Anomers are the two structural forms of same molecule which differentiate from each other only in the direction of the OH (hydroxyl) group present at the hemiacetal carbon (C1). The molecule having group in the upward direction is called as anomer. The molecule having group in the downward direction is called as anomer.
1.
The chair conformation of glucose is as follows:
The form of glucose is as follows:
2.
The chair conformation of glucose is as follows:
The form of glucose is as follows:
Therefore, the form of glucose is as follows:
Therefore, the form of glucose is as follows:
Glucose generally exists in ring (cyclic) form. A Haworth projection shows the orientations of the hydroxyl...
Convert the Fischer projection to the Haworth projection of the
B-furanose form by moving the substituents to the appropriate
positions. The anomeric carbon is shown.
Convert the Fischer projection to the Haworth projection of the B-furanose form by moving the substituents to the appropriate positions. The anomeric carbon is shown. CH2OH =0 HO—C—H Cyclization H-¢-OH Answer Bank CH OH H—¢-OH CH,OH CH2OH
Convert the Fischer projection to the Haworth projection of the B-pyranose form by moving the substituents to the appropriate positions. The anomeric carbon is shown. EK Cyclization } CH2OH Answer Bank CH,OH OH H
Draw the Haworth projections (cyclic forms) of L form along with alpha and beta of each of the following: Glucose (glucopyranose), Mannose (mannopyranose), Galactose (galactopyranose), Fructose, Fructofuranose, Fructopyranose
Show the structure of a disaccharide in Haworth projection with two D-glucose units connected with a beta-1,4'-glucosidic-linkage. H H OH HO H H OH H OH CH2OH
Draw the cyclic Haworth projection of the beta-furanose form of D-fructose. Show the mecahnism behind it.14 (2).pdf
The predominant form of glucose in solution is a ring structure represented by the Haworth projection. Why then does glucose give a positive test and react completely in reactions which are characteristic of its straight chain form?
22. Convert the following Fisher projection into a Haworth
projection. Draw only the alpha anomer (12 points)
21. Are the following pairs of carbohydrates the same, completely different, constitutional isomers or stereoisomers? (12 points at 3 points each) CHO CHO CHO сњон он OH он он CH2OH он он он он он но он но но он он CH2OH CH2OH он CHO CHO CHO сњон он он он он он но он но но Ho но он но он OH...
Select all of the descriptions that are accurate for this molecule of glucose CH2OH н с— о, н VH С он н C OH но с H Он it is a hexose it is in the alpha form it is in the beta form it is a furanse it is a pyranose it is a Haworth projection It is a Fischer projection Select all of the descriptions that are accurate for this molecule. CH-он Он Он ОН It is a...
1. Below is a monosaccharide in its cyclic (ring) form. OH он Linear form OH a) Is the monosaccharide the a-or the B-anomer? b) Label each carbon with its carbon number. c) Draw the linear form of this monosaccharide with the correct chirality in the box at right. 2. a) Draw the linear form of D-ribose: b) Ribose can form a pyranose ring. Draw an electron arrow on your linear ribose drawing above, indicating which nucleophile attacks which electrophile to...
D-glucose is shown below in its straight-chain and ring
forms.
A) Put an asterisk next to each chiral carbon in the
straight-chain form of D-glucose.
B) Label the given ring forms as the alpha or beta anomer of
D-glucose. Draw the other anomer. Which one is more stable, the
alpha or beta anomer? Explain your logic.
H Он он но H Но Но Н он H он он н но но