Question

Glucose generally exists in ring (cyclic) form. A

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Answer #1
Concept and reason

The concept used to solve this question is to draw the α\alpha and β\beta forms of glucose.

Fundamentals

Haworth projection is the method of representing monosaccharides in a cyclic ring.

Similarly, glucose is a monosaccharide and can be represented as Haworth projection.

Anomers are the two structural forms of same molecule which differentiate from each other only in the direction of the OH (hydroxyl) group present at the hemiacetal carbon (C1). The molecule having OH - {\rm{OH}} group in the upward direction is called as β\beta anomer. The molecule having OH - {\rm{OH}} group in the downward direction is called as α\alpha anomer.

1.

The chair conformation of glucose is as follows:

HO
HON
WOH
OH

The α\alpha form of glucose is as follows:

СН,ОН
H
-о,
Н
ОН
н
НО
ОН
н
ОН
a-D-glucose

2.

The chair conformation of glucose is as follows:

The β\beta form of glucose is as follows:

СН,ОН
-0,
H
ОН
ОН
Н
ОН
ОН
B-D-glucose

Ans: Part 1

Therefore, the α\alpha form of glucose is as follows:

СН,ОН
H
-о,
Н
ОН
н
НО
ОН
н
ОН
a-D-glucose

Part 2

Therefore, the β\beta form of glucose is as follows:

СН,ОН
-0,
H
ОН
ОН
Н
ОН
ОН
B-D-glucose

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