Question
D-glucose is shown below in its straight-chain and ring forms.

A) Put an asterisk next to each chiral carbon in the straight-chain form of D-glucose.

B) Label the given ring forms as the alpha or beta anomer of D-glucose. Draw the other anomer. Which one is more stable, the alpha or beta anomer? Explain your logic.
H Он он но H Но Но Н он H он он н но но
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Answer #1

* chiral carbon 141 all tour substituents are different 4 - cliral carbon HO -Anonuric carbon Mo a - Anomer - B - Anoner .

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