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2. Convert each sugar below to its Haworth form. Draw the alpha anomer for a, the beta for b. CH OH c=0 но-с-н HO-c-H H-C-OH

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Answer #1

at cyclic anomeric carbon (first chiral carbon) in sugar, if oh left then it is ß it Oh Right then it is a coH SH₂OH HoHe- Ho

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