Question

ch 10 4b

Review I Constants Periodic Table The ideal gas law (PV = nRT) describes the relationship among pressure P, volume V, temperature T, and molar amount n. When n and V are fixed, the equation can be rearranged to take the following form where k is a constant: Part B At standard temperature and pressure (0 C and 1.00 atm), 1.00 mol of an ideal gas occupies a volume of 22.4 L What volume would the same amount of gas occupy at the same pressure and 50 C? -k or ( nR final Express your answer with the appropriate units. initial View Available Hint(s) When n and P are fixed, the expression becomes () or HA initial final Value Units Vfinal = Previous Answers Submit X Incorrect; Try Again; 4 attempts remaining

Answer 1

The given problem is based on ideal gas equation PW, = nRT, -(i) [ Given: Pressure (P) and amount / P/2 = nR Tz - Lii) I. of gas (n) is constant , Dividing equ li) by cii) we get- 1 Giren: Vi = 22:44 ; T, = 0°C -(0+273) K= 273K V2 = ? ; T2 = 50°C = (50 +273) K = 323K the values in eqh uili) we get Plugging 22.4L - 273 K. 323 K V2 V, 22.4L X 323 = 26.5L 273 volume occupied (V2) at 50°c is 26.5L