Question

Can anyone help me find the answer to this? Thank you! part B please

View Available Hint(s) The ideal gas law (PV = nRT) describes the relationship among pressure P, volume V, temperature T, and molar amount n. When n and V are fixed, the equation can be rearranged to take the following form where k is a constant: Pfinal = 2.61 atm f = np = k or ( a = ( ) final initial Submit Previous Answers When n and P are fixed, the expression becomes Correct 1 = m = k o () szitia = () final The pressure of a fixed amount of gas at constant volume is directly proportional to its temperature: the higher the temperature, the greater the pressure. That is why warnings on many household containers read: "Contents under pressure. Do not place near sources of heat." If such a container is overheated, it might explode. Part B At standard temperature and pressure (0 °C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L. What volume would the same amount of gas occupy at the same pressure and 25 °C ? Express your answer with the appropriate units. View Available Hint(s) ? CHÅR Vimal = Value O 2 Units

Answer 1

Solution's are fixed, when no. of moles and bressure "The c oussion de cemesse intelis IT initial Tinitial Final Initially?- volume (Winitial = 22:42 elements Temperuture Tinitial O'cs (0+273-15) 273.15 K Final volume (V) final = ? Temperature (1) Final 25'c » (25+273:15.)k - 298.15k According to eauution ci) Vrinal - Vinitial & Trinal . Tinitial VEinel = 22:41 X 298.15K 273.15 K IV Final = 22.45 litre