Question

A study done by researchers at a university concluded that 30​% of all student athletes in this country have been subjected to some form of hazing. The study is based on responses from 1,800 athletes. What are the margin of error and​ 95% confidence interval for the​ study?

Answer 1

Given that, proportion ( p ) = 0.30

sample size ( n ) = 1800

A 95% confidence level has significance level $(\alpha)$ = 0.05 and critical value is, $Z_{\alpha/2} = 1.96$

We want to find, the margin of error ( E ),

$E = Z_{\alpha/2} * \sqrt { \frac { p * (1-p)}{n }}= 1.96 * \sqrt {\frac { 0.30*(1-0.30)}{1800}}= 0.021170$

Therefore, the margin of error is 0.0212

Answer 2

A research calculated the percentages of students who are female at a sample of colleges and universities. The unit of analysis in this study was