The confidence level in a confidence interval is established by
A Z-value, such as 1.96 for a 95% confidence interval |
A t-value, using the appropriate degrees of freedom and the level desired |
The appropriate statistic for the test distribution |
The F statistic, using the appropriate degrees of freedom and the level desired |
The confidence level in a confidence interval is established by A Z-value, such as 1.96 for...
True or False? The higher the confidence level, the narrower is the confidence interval for the mean. Select an answer The most efficient point estimator for the population mean ù is the sample median . Select an answer • To reduce the width of a confidence interval, we can increase the sample size n. Select an answer • As long as the population is normal with variance o’, the statistic (n-1) S2 has a Chi-squared 02 distribution with n degrees...
The z-value used in a 80% Confidence Interval is 1.645 2.575 1.282 1.96
(6 points) Match the confidence level with the confidence interval for u. 1. 1.96 () 2.3 +1.645 () 3. + 2.575 () A. a. 95% B. b. 90% C. c. 99%
determine the level of confidence given the confidence coefficient z(a/2) = 1.96
Consider a z confidence interval for the population mean. If the confidence level decreases but everything else stays the same then we can expect the size of the interval to: A test was conducted to determine if HO: Mu = 52.7 should be rejected in favor of Ha: Mu > 52.7 where mu refers to the population mean. A sample was selected and the resulting test statistic was found to be 2.15. What is the p-value for the sample statistic?...
The
critical value of z for 95% level of confidence is +/- 1.96 the
picture of a spreadsheet contains the proportions of Medicare cases
in 29 southwest Pennsylvania hospitals.
A. How would you characterize children’s hospital?
B. What should we do with Children’s If we are interested in
calculating the mean?
C. The mean proportion of Medicare cases is including
children’s is 0.449. Without children’s it would be .465. The
standard deviation is 0.131. Use a z test (two tails)...
A 50% confidence level has a confidence interval of 0.6745. A 90% confidence level has a confidence interval of 1.96. A 99% confidence level has a confidence interval of 2.57. A critical distance is measured 17 times. The mean is 317.6 feet, the sample standard deviation is 0.46 feet. The standard error of the mean value with a confidence level of 90% is (A) (2.57) (0.46) 17 (B) (1.96) (0.46) 17 D. (1.96) (0.46) V17 (D) (0.46) (17) 1.96
Using Excel, find the value of the 95% confidence interval for a single sample using both the z variable and the student's t-distribution where the mean is 10.00 with a standard deviation of 0.50. When calculating the confidence interval for the z-value, assume any value of n is a large sample, and when calculating the confidence interval for the for the student's t-distribution, assume any value of n is a small sample. Compute the confidence intervals for: a. n 50...
In confidence interval estimation, we define the level of significance as: a) 1 + confidence level I. b) confidence level-1 c) 1-confidence level d) α-1 e) 1-a If we are given a sample with ơ unknown, we should use the t-distribution unless the sample size a) 5 gb) 25 : c) 30 d) 500 e) none of these In hypothesis testing, we make a Type II error when we: a) fail to reject a true Ho b) reject a true...
19. Given a test statistic: Zc 2 and the known Z-values for common confidence intervals: 1.645, 1.96, and 2.576 for the 90%, 95% and 99 % confidence levels respectively. Can you reject the null hypothesis at the 95% confidence level? Be sure to define and discuss the test statistic and Z-values in your answer.