d (13%) Problem 5: Aperson's eyes are h = 1.6 m above the floor as he...
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.275. 33% Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? d; = -0.89 d;=-0.89 Correct! 33% Part (b) What is the focal length of the mirror, in meters? f = -0.821 sino cos tan() cotan asino acos atan) acotan sinh cosh tanh) cotanh) Degrees Radians...
A person whose eyes are at a height H above the floor stands a distance L in front of a vertical plane mirror whose bottom edge is h above the floor , as seen in the figure below . Find an expression for the horizontal distance x to the base of the wall supporting the mirror of the nearest point on the floor that can be seen reflected in the mirror , Your expression should be in terms of the...
please see parts a-d at bottom of picture. Thank you. (10%) Problem 8: An object rolls off a tabletop with a horizontal velocity vos 8 m/s. The table is at a height yo 1.85 m, above the floor. Use a coordinate system with its origin on the floor directly beneath the point where the object rolls off the table, its horizontal x-axis lying directly beneath the object's trajectory, and its vertical y-axis pointing up. 25% Part (a) How long, in...
A person whose eyes are H = 1.55 m above the floor stands 2.20 m in front of a vertical plane mirror whose bottom edge is 38 cm above the floor (Figure 1) .
(13%) Problem 7: An object 1.4 cm high is held 2.95 cm from a person's cornea, and its reflected image is measured to be 0.169 cm high. > 33% Part (a) What is the magnification? m= 1 Grade Summary Deductions Potential 100% 0% o E sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh) | tanh() | cotanh() | Degrees Radians ( 7 8 9 HOME 4 5 6 1 2 3 | + |-| 0 | || END...
(5%) Problem 13: A camera with a 50.0 mm focal length lens is being used to photograph a person standing 3.5 m away. * 50 % Part (a) How far, in centimeters, must the film be from the lens? d;= 3.5 * 10(-2) Grade Summary Deductions 0% Potential 100% v E HOME sin() cos( tan() cotan asin( acos atan acotan sinh cosh tanh() cotanh0 Degrees Radians ( 7 8 9 4 5 6 * 1 2 3 + - 0...
A person whose eyes are 1.70 m above the floor stands in front of a plane mirror. The top of her head is 0.140 m above her eyes. (a) What is the height of the shortest mirror in which she can see her entire image? (b) How far above the floor should the bottom edge of the mirror be placed?
a. His eyes are 1.79 m above the floor, and the top of his head is 0.13 m higher. Find the height (in m) above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. Top = ___m Bottom = ___m b. How is the distance d from the bottom of the mirror related to the man's height h? d = ___ Suppose a man...
(25%) Problem 3: A mass m = 0.65 kg hangs at the end of a vertical spring whose top end is fixed to the ceiling. The spring has spring constant k = 65 N/m and negligible mass The mass undergoes simple harmonic motion when placed in vertical motion, with its position given as a function of time by y(t) A cos(ot - *), with the positive y-axis pointing upward. At time t = 0 the mass is observed to be...
(20%) Problem 3: Acandle (h, = 0.22 m) is placed to the left of a diverging lens (f= -0.074 m). The candle is do = 0.12 m to the left of the lens 25% Part (a) Write an expression for the image distance, dj. Grade Summary 0% Deductions Potential 100% ( 0 Submissions 7 НОМЕ Attempts remaining: 5 (0% per attempt) detailed view AA d 4 5 6 а f 3 j k 0 END VO BАСKSРАСЕ P S DEL...