Doug hits a hockey puck, giving it an initial velcoity of 6.0
m/s. If the coefficient of kinetic friction between ice and puck is
0.050, how far will the puck slide before stopping?
acceleration = F/m = (coef. friction)
g
acceleration = 0.050 * 9.81 m/s2
= 0.4905 m/s2
-----------------------------
v = at
6 = 0.4905 t
t = 12.23 s
----------------------------
s = vt - 0.5at^2
= (6 * 12.23) - (0.5 * 0.4905 *
12.23^2)
s = 36.7 m
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