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Please write this in computer, not by the hand. To compute the confidence level and the...

Please write this in computer, not by the hand.

To compute the confidence level and the sample size lets vary the confidence level and the accuracy of the textbook example of the mean burn of the sample of propellants.

Remember that in the textbook example if the

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Answer #1

a 95% confidence interval for population mean

Vn Vn

Width of the 95% confidence interval for population mean

=2*z_{0.025}*rac{sigma }{sqrt{n}}

Width of the 99% confidence interval for population mean

=2*z_{0.005}*rac{sigma }{sqrt{n}}

Now, z_{0.005} = 2.57583 > z_{0.025} = 1.95996 ,

so, Width of the 99% confidence interval for population mean > Width of the 95% confidence interval for population mean

1. ans-> b) False

2. Margin of error =z_{0.005}*rac{sigma }{sqrt{n}}

Margin of error is inversely proportional to sample size(n) that means as margin of error decreases as sample size increases.

ans-> a) True

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