One of the students on the roller Coaster records the trip w/ a 1.5kg video camera...

Question

Question

One of the students on the roller Coaster records the trip w/ a 1.5kg video camera in what is the coasters speed as it goes

Answer 1

Answer #1

Initial energy of the roller coaster at height hi = 48 m moving with velocity V1 = 0.5 m/s2 is E; = mghi +-mvi

(Assuming there is no friction and energy loss)

Final energy of the roller coaster at height h2 = 16 m moving with velocity v_2 is E = mgh + mua

Conserving the energy of roller coaster at the two positions,

E = Es

mghi += mvị = mgh2 += mv

gha + 3v1 = gh2 +

V2 = 29(hı – h2) + v1

U2 = 12 * 9.81(48 – 16) + (0.5)2 = 25.06 m/s

Speed of roller coaster on 16 m tall hill is V2 = 25.06 m/s

Answer 2

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