Question

Consider the three alkoxide bases: methoxide, ethoxide, and tert-butoxide. In what way is the reactivity of tert-butoxide different from the others in elimination reactions?

Consider the three alkoxide bases: methoxide, ethoxide, and tert-butoxide. In what way is the reactivity of tert-butoxide different from the others in elimination reactions? methoxide ethoxide tert-butoxide o tert-butoxide is a much stronger base than the others and so only performs o tert-butoxide is a much weaker base than the others and so doesn't perform E1 elimination reactions elimination reactions. tert-butoxide has more steric bulk than the others so it is more likely to make the Hofmann elimination product. the Zaitsev elimination product.

Answer 1

c).tert-butoxide has more steric bulk than the others so it is more likely to make the Hoffman elimination product.

tert-butoxide is a very bulky molecule.it can be used to form yhe less substituted alkenes in E2 elimination reactions.Most of the time elimination reactions favor the more substituted akene which is the zaitsev product.However when tert-butoxide is used,it will preferentially remove the proton from the smaller group.this produces the Hoffman product.