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Provide the products obtained in each of the following four reactions. 1. Hydrogenation of (4S)-4-methyl-1-hexyne with...

Provide the products obtained in each of the following four reactions.

1. Hydrogenation of (4S)-4-methyl-1-hexyne with H2 and Palladium

2. Hydrogenation of (3S)-3-methyl-1-pentyne with H2 and Palladium

3. Hydrogenation of (4S)-4-methyl-1-hexyne with Lindlar catalyst

4. Hydrogenation of (3S)-3-methyl-1-pentyne with Lindlar catalyst

5. Which of the above four reactions does not provide optically active products?

Provide the IUPAC names of the reactants that would react with HgSO4, and H2SO4 under oxymercuration-demercuration conditions to provide the the following compounds A-F.

1. Reactant that provides Compound A would be

2. Reactant that provides Compound B would be

3. Reactant that provides Compound C would be

4.Reactant that provides Compound D would be

5. Reactant that provides Compound E would be

6. Reactant that provides Compound F would be

7. Reactant that provides Compound G would be

8. Reactant that provides Compound H would be

Provide the products obtained in each of the follo

Provide the IUPAC names of the reactants that would react with BH3 followed by NaOH, H2O2 under hydroboration-oxidation conditions to provide the the following compounds A-F.

1. Reactant that provides Compound A would be

2. Reactant that provides Compound B would be

3. Reactant that provides Compound C would be

4.Reactant that provides Compound D would be

5. Reactant that provides Compound E would be

6. Reactant that provides Compound F would be

7. Reactant that provides Compound G would be

8. Reactant that provides Compound H would be

Provide the IUPAC names of the following four alkynes A-D. Then, provide the IUPAC names for the products obtained upon reacting these compounds A-D with H2 and Lindlar catalyst.

IUPAC name for Compound A:

IUPAC name for Compound B:

IUPAC name for Compound C:

IUPAC name for Compound D:

IUPAC name for the product obtained from Compound A:

IUPAC name for the product obtained from Compound B:

IUPAC name for the product obtained from Compound C:

IUPAC name for the product obtained from Compound D:


Three isomeric compounds A-C (molecular formula C10H18) react with KMnO4 to provide the products as shown below. The same compounds A-C react with Li/NH3 under dissolving metal reduction conditions to provide the three isomeric products D-F (molecular formula C10H20). Based on this information, provide the IUPAC names for all the six compounds A-F.

IUPAC name for compound A:

IUPAC name for compound B:

IUPAC name for compound C:

IUPAC name for product D:

IUPAC name for product E:

IUPAC name for product F:

Three isomeric compounds A-C (molecular formula C10H18) react with KMnO4 to provide the products as shown below. The same compounds A-C react with Li/NH3 under dissolving metal reduction conditions to provide the three isomeric products D-F (molecular formula C10H20). Based on this information, provide the IUPAC names for all the six compounds A-F.

IUPAC name for compound A:

IUPAC name for compound B:

IUPAC name for compound C:

IUPAC name for product D:

IUPAC name for product E:

IUPAC name for product F:

Provide the IUPAC names for the following five compounds in the reaction sequence provided below.

IUPAC name for Compound A:

IUPAC name for Compound B:

IUPAC name for Compound C:

IUPAC name for Compound D:

IUPAC name for Compound E:

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Answer #1

This is a very long question. I am going to answer you the first quwestion with the four subparts.

Please fell free to repost the rest so we can gladly help you

Ok the for the first question we should know the difference between the hydorgenation with palladium and the lindlar catalyst.

When we hidrogenate with the Pd, the hidrogenation of the bonds wont stop until we get the alkane. it means that all of the \pi bonds will be hidrogenated. But when we use the Lindlar catalyst, it will stop in the alkene, it means it will only hidrogenate 1 \pi bond, The lindar catalyst does not hydrogenate alkenes.

Thus we will have this reactions

CH CH CH CH CH CH (4S-4-methylhex-1-yne Pd Pd (3S)-3-methylhexane (4S)-4-methylhex-1-ene CH CH CH Нас CH Pd Pd 3-methylpentan5. For a molecule can be called optically active the mirror image can't be superimposed on her.

If we can take a look on the product of the reaction #2. Its mirror image can be superimposed the this is not anoptically active produce

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