You need to use a 22-cm-focal-length lens to produce an inverted image three times the height of an object.
At what distance from the object should the lens be placed?
answer) u=object distance
v= image distance
we have v/u=-3
v=-3u
from lens equation
1/f=1/v-1/u
1/22=-1/3u-1/u
1/22=-1-3/3u
1/22=-4/3u
u=-29.3cm
so the answer is -29.3cm or -29cm.
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