Question

8. In a clinical trial of a drug used to help subjects stop​ smoking, 818 subjects were treated with 1 mg doses of the drug. That group consisted of 41 subjects who experienced nausea. The probability of nausea for subjects not receiving the treatment was 0.0096. Complete parts​ (a) through​ (c).

Assuming that the drug has no​ effect, so that the probability of nausea was 0.0096​, find the mean and standard deviation for the numbers of people in groups of 818 that can be expected to experience nausea.

The mean is____ people

The standard deviation is ____ people

2. Based on the result from part​ (a), is it unusual to find that among 818 people, there are 41 who experience ​nausea? Why or why​ not?

A. It is not unusual because 41 is within the range of usual values.

B. It is not unusual because 41 is outside the range of usual values.

C. It is unusual because 41 is within the range of usual values.

D. It is unusual because 41 is outside the range of usual values.

3. Based on the preceding​ results, does nausea appear to be an adverse reaction that should be of concern to those who use the​ drug?

A. The drug does appear to be the cause of some nausea. Since the nausea rate is still quite low​ (about 4​%), it appears to be an adverse reaction that does not occur very often.

B. The drug does appear to be the cause of some nausea. Since the nausea rate is quite high​ (about 4​%), it appears to be an adverse reaction that occurs very often.

C. The drug does not appear to be the cause of any nausea.

Answer 1

8)

The mean is =np=7.8528

std deviation =sqrt(np(1-p))=2.7888

2)

D. It is unusual because 41 is outside the range of usual values.

3)

A. The drug does appear to be the cause of some nausea. Since the nausea rate is still quite low​ (about 4​%), it appears to be an adverse reaction that does not occur very often.