Question

In a clinical trial of a drug intended to help people stop smoking, 127 subjects were treated with the drug for 11 weeks, and 18 subjects experienced abdominal pain. If someone claims that more than 8% of the drug's users experience abdominal pain, that claim is supported with a hypothesis test conducted with a 0.05 significance level. Using 0.17 as an alternative value of p, the power of the test is 0.95. Interpret this value of the power of the test. hypothesis of p= when the true proportion is actually That is, if the % chance of supporting the claim that the proportion of users who experience The power of 0.95 shows that there is a % chance of rejecting the proportion of users who experience abdominal pain is actually then there is a abdominal pain is than 0.08. (Type integers or decimals. Do not round.)

Answer 1

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Given data: . The power of 0.95 shows that there is a 95% Chance of rejecting the Null hupothesis of P = 70.08] when the true proportion is actually 10.17. That is, if the Proportion of users who experienced abdominal pain is actually [017 then there is a las % chance of supporting the claim that the proportion of users who experience CScanned with redosenador pain is more than 0.08