Question

Suppose 210 subjects are treated with a drug that is used to treat pain and 51 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: P=0.20 H:p*0.20 O B. Ho: p=0.20 Hyp<0.20 Oc. Họ p>0.20 Hy: p=0.20 OD. Ho: p=0.20 Hy:p>0.20 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is - (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test.

Answer 1

Hypotheses: H:p=0.20. That is, 20% of users develop nausea. H:p>0.20. That is, more than 20% of users develop nausea. Therefore, the correct option is D. Test statistic: 2= P-Po ;p=*= 31 = 0.2429 P. (1-p.) n 210 0.242 0.2429-0.20 10.20(1-0.20) V 210 0.0429 0.0276 =1.55 P-value: G fx =1-NORM.S.DIST(1.554347,1) E F 0.060051! Therefore, the P-value is 0.060.

Conclusion: If, P-value < level of significance, then reject the null hypothesis. Here, P-value (0.060)> level of significance (0.05), then do not reject the null hypothesis. Therefore, fail to reject Ho. There is not sufficient evidence to warrant support of the claim that more than 20% of users develop nausea. Thus, the correct option is D.