With a lens, both the height and width of the image exhibit magnification. With a mirror, only the height is affected. Try to explain this difference.
The key reason for such difference might be stated like this:
In case of a mirror the light undergoes reflection through the mirror surface so it just travels in straight direction and changes it's path without undergoing bending (by using law of reflection) and in such case only the height of the object can change.
But when it comes to Lens, the light passes through the lens material and undergoes refraction (bending due to difference in refractive index of lens and surrounding medium). Due to this bending the image formed by the refracted light not only has different height but also different width.
With a lens, both the height and width of the image exhibit magnification. With a mirror,...
How will an image appear with a mirror or lens with a negative magnification? A. Farther from the mirror/lens than the object B. Closer to the mirror/lens than the object C. Inverted D. Smaller than the object
The magnification of an image in a lens or mirror is given by the following equations? (SELECT ALL THAT APPLY) OM = d. OM= d. do OME hi do M hi ho
What is the height of the cup's mirror image? Number 23 cm Is the image upright or inverted? upright Previous ? Try Again Next Exit lanation lthough you are neither given the magnification m nor asked for it, the magnification relationship will be useful. It elates the object distance do, the image distance d, the object height ho, and the image height h In ecause you are only given two of these quantities, you must first use the information regarding...
Consider a spherical mirror and lens separated by 45 cm. The mirror is on the left with a focal length of 100 cm. The lens is on the right with a focal length of −20 cm. A 5 cm tall object is placed 20 cm to the left of the lens. a) If you only consider the rays that move to the right from the object, fully characterize the final image in the system. In other words provide final image...
A concave lens has a focal length of -36 cm. Find the image distance and magnification that results when an object is placed 19 cm in front of the lens. (Use the proper sign convention for both quantities.) When an object is located 61 cm to the left of a lens, the image is formed 25 cm to the right of the lens. What is the focal length of the lens? An object with a height of 2.22 cm is...
A positive magnification for a mirror means that the image is inverted, and the mirror is convex. the image is inverted, and the mirror could be either concave or convex. the image is upright, and the mirror is convex. the image is upright, and the mirror could be either concave or convex. the image is inverted, and the mirror is concave.
The object in the figure beside is mid-way between the lens and the mirror, which are separated by a distance d-25.0 cm. The magnitude of the mirror's radius of curvature is 20.0 cm, and the lens has a focal length of-16.7 cm. Lens Object Mirronr (A) We first study the image formed by the lens only (As the spherical (a) Describe the image formed by the lens (location, magnification, real or virtual and (b) Construct a ray diagram of this...
A lens and a concave mirror are separated at 20.0 cm as shown in Figure . The lens and the mirror have focal lengths of 2.0 cm and 6.0 cm, respectively. Assume that an object is placed upright to the left of the lens. The image formed due to light passing through the lens twice is located at 6.0 cm to the right of the lens. (i) Determine the position of the object with respect to the lens. (ii) Describe...
An image produced by the mirror with a magnification m=+4. The focal length of the mirror is 20 cm (note that the sign of f is not given). (a) What is the sign of f? (b) How far in front of the mirror is the object located? (c) What is the image distance? (d) Is the image real or virtual? (e) What kind of mirror is that? Make sure to elaborate on part (a)
A biconvex lens sits between an object and a concave spherical mirror. The lens has a focal length f and the mirror has a radius of curvature of R. The object is a distance 2f from the lens and the distance from the lens to the mirror is 2f + R. The object is illuminated and light scattered from the object shines through the lens to the mirror, reflects, travels back through the lens, and forms a final image. (a)...