Question

A m=6 gram object is accelerated at a rate of a=3.4 m/s2. What is the magnitude of 103×F where F is force the object experience? Express the answer with one decimal place (don't forget to add the unit).

Answer 1

Here we have given mass

m=6x10⁻³ Kg and a =3.4m/s²

Now by newton second law of motion

F=ma

F=6x10⁻³ x3.4 = 20.4 x10⁻³ N= 20.4 mN

now we have to find

10³ xF =10³ x 20.4x10⁻³ =20.4 N

Answer 2

Rate of a=3.4 m/s2