which way is the simplest to solve this problem? is there other way than using gamma function ? please add the different ways to solve this problem. Thank you !!!
6)
X follow binomial distribution
n = 300 and p = 0.1
You can use normal approximation
mean = np = 300 * 0.1 = 30
sd =sqrt(npq) = sqrt(300 * 0.1 * 0.9) = 5.1962
Z = (X - mean)/sd = (X - 30)/5.1962
P(X > 35) = P(X >= 35.5) { contnuity correction}
= P (Z > (35.5 - 30)/5.1962)
= P (Z>1.06)
=0.1446
b)
P(28 < X< 31)
= P(28.5 <= X< = 30.5)
= P ( −0.29<Z<0.1 )
=0.1539
Please post next question again
which way is the simplest to solve this problem? is there other way than using...
which way is the simplest way of solving this problem?
is there other ways to solve it without using gamma function? if
so, please show the different ways! thank you so much !
Let Yi, Y2, ..., Yso be a sequence of exponentially distributed random variable with parameter-4 , and Y =/i/40. Find P(Y<2) 40 /mail.google.com/mail/u/0/#inbox/FMcgxwBVCzcfwVpqNzGmrwWBgGqrN?projector-1 &messagePartid=0.2
I know this could be solve using the gamma function,
is there other way to solve this problem? if so could someone show
me how to do it both ways, meaning using the gamma function and any
other way possible. please be as detailed as possible. Thank you
and I'll rate
Let Yi, Y2...., Y4o be a sequence of exponentially distributed random variable with parameter λ=.4, and Y=Σ Y/40, Find P(Y<2) 40
lambda=.4 please show all steps!! as detailed as
possible, thank you so much for your time
Let Yi, Y2, ..., Yso be a sequence of exponentially distributed random variable with parameter λ=.4 , and Y-31/40, Find P(Y<2) 40
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