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7. 0/2 points | Previous Answers OSUniPhys1 22.3.P.02. My Notes Ask Your Tea The charges q1 = 2.2x 10-7 c, q2 =-7.5x 10-7 C, and q3 =-1.4 × 10-7 C are placed at the corners of the triangle shown below. What is the force on q1 (in N)? (Assume that the +x- axis is to the right and the ty-axis is up along the page.) 5.0 m 3.0 m 4.0 m 93 92 (4.572e-5)-(6.644-5 N

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Answer #1

Force due to a charge 'q2' on another charge 'q1' with the vector joining them being r12 is given by the Coulomb's law is-

small overrightarrow{F} = rac{k ::q_{1} :: q_{2}}{(|| overrightarrow{r_{12}} ||)^2}widehat{r_{12}}

As Force is a vector quantity, so you will have to do vector addition of two vectors to get the net force on q1.

be plated at bn So 3 1 0,3>- 2 1 5 33 31 23 31 し29 -3.08x10-5 ) 21 (3x 10g)선·5x10-7)(9.2x16) (s J 5 5 : (-5,94 x105 (tt. 752×10-5)? -(8.56#x10-5)3 So, net tere 2 1 (-3.csm)s + (n-sw。S1-3 sy 지瀏 4.752 x16-5人一6.644x 1-53

Your answer is correct mathematically. I think there is a technical mistake that you have made. You need to put the unit vectors i and j out of the parenthesis.

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7. 0/2 points | Previous Answers OSUniPhys1 22.3.P.02. My Notes Ask Your Tea The charges q1...
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