Question

Part A Two vectors A and B have magnitude A = 3.08 and 2.98. Their vector product is A × Β--508k + 2.08 i. What is the angle between A and B? Submit Previous Answers Request Answer X Incorrect: Try Again; 2 attempts remaining

Answer 1

We know

$|A X B| = |A|.|B| Sin(\Theta )$

$Sin(\Theta )=|A X B| /|A|.|B|$

$(\Theta )= Sin^-1(|A X B| /|A|.|B|)$

|A X B| = √((-5.08 × -5.08) + (2.08 × 2.08) = 5.4893

given |A| = 3.08

|B| = 2.98

$\Theta =$ Sin ^-1( 0.5980 ) = 36.72 degree