Question

Identify two ions that have the following ground-state electron configurations.

Part A [Ar] Check all that apply. Lit Ca2+ ОСІ Na+ Fe2+

Part C [Kr]58-4d10 Check all that apply. Sb3+ Sn- Sn2+ Pdt O Fr+

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Answer #1

Part C

Atomic number of Antimony (Sb) = 51

Electronic configuration of Sb is [Kr]4d10 5s2 5p3

Electronic configuration of Sb​​​​​3+ is [Kr]4d10 5s2

It is similar to given electronic configuration of Cadmium (Cd)

Atomic number of Tin (Sn) = 50

Electronic configuration of Sn is [Kr]4d10 5s2 5p2

Electronic configuration of Sn​​​​​- is [Kr]4d10 5s2 5p3

It is not similar to given electronic configuration of Cadmium (Cd)

Atomic number of Tin (Sn) = 50

Electronic configuration of Sn is [Kr]4d10 5s2 5p2

Sn​​​​​2+ ion is formed by removal of two electrons from Sn

Electronic configuration of Sn​​​2+ is [Kr]4d10 5s2

It is similar to given electronic configuration of Cadmium (Cd)

Atomic number of Palladium (Pd) = 46

Electronic configuration of Pd is [Kr]4d10

Electronic configuration of Pd2+ is [Kr]4d8

​​​​​​It is not similar to given electronic configuration of Cadmium (Cd)

Atomic number of Francium is 87.

It's electronic configuration is [Rn] 7S1

Electronic configuration of Fr​​​+ is [Rn]

It is not similar to given electronic configuration of Cadmium (Cd)

Sb​​​​​3+ and Sn​​​​​2+ have the given electronic configuration.

Part A:

TYD Electronic Configuration of As is 15 25 206 35 3p6 (Alone Number = 18) Electronic Configuraken of tils/2s! het is formed

Electonic Configurden of Na (2=11) is 15257 2p6gs! Electronic Configuraken of Natý - 15 25 26 Not Similar to Ar Electronic co

Calcium a( Ca​​​​​2+)chloridens (Cl​​​​​-) have electronic configuration of Argon

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