Homework Answers
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All charges are equal, electric field due to diagonally opposite charges will be equal and opposite and cancel each other.
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Problem 4 (25 pts). Without doing any calculation, what is the value of the electric field...
Problem (25 pts). Without doing any calculation, what is the value of the electric field at...
Problem (25 pts). Without doing any calculation, what is the value of the electric field at the origin O due to the configuration of 4 point charges shown in the Figure below? Justify your answer with 1 short sentence Bonus (Optional) Problem 5 (25 pts). The Figure below shows a thin nonconducting rod of length L-20 em A total charge of Q-8C is spread uniformly along it. What is the electric field vector at the point P which is located...
All charges are the same distance from the origin. 1) Without doing any calculations, does the...
All charges are the same distance from the origin.
1) Without doing any calculations, does the electric field at
the origin in diagram 1 have a magnitude that is greater than, less
than, or equal to the magnitude of the field at the origin in
diagram 2? Justify.
2) If the distance between the charges and the origin is 6.1cm.
For each diagram shown, determine the magnitude and direction of
the electric field at the origin. (show calculations/equations)
ty ty...
Problem 1 (25 pts) A. [4 pts) A particle with charge q = -1.5 x 10-15...
Problem 1 (25 pts) A. [4 pts) A particle with charge q = -1.5 x 10-15 C creates an electric field Ē, at location A. What is the direction of E, at location A? Refer to the rosette in the figure and select a letter that corresponding to the best choice of direction. A B C D E F G H I A X I - zero magnitude B. (4 pts) Next a neutral metal block is placed in the...
Problem Solving What is the value of the electric field at Point A (halfway between the...
Problem Solving What is the value of the electric field at Point A (halfway between the two positive charges) due to the given charge distribution? 6.00 c A 1.50pC -2.00 μ 3.00 cm2.00 cm Use the superposition principle- the Electric field as some distance r from a point charge Q is: 2
homework due soon !! Question 2 25 pts A pair of point charges, 91 = +7.50...
homework due soon !!
Question 2 25 pts A pair of point charges, 91 = +7.50 C and q2 = -5.00 uC are moving as shown below with speeds v1 = 9.50 x 104 m/s and V2 = 7.00 x 104 m/s. When the charges are at the locations shown in the figure a) what is the net magnetic field at the origin (magnitude and direction)? (10 pts) b) what is the net electric field at the origin (magnitude and...
homework due soon!! part B & C please Question 2 25 pts A pair of point...
homework due soon!!
part B & C please
Question 2 25 pts A pair of point charges, 91 = +7.50 C and q2 = -5.00 uC are moving as shown below with speeds v1 = 9.50 x 104 m/s and V2 = 7.00 x 104 m/s. When the charges are at the locations shown in the figure a) what is the net magnetic field at the origin (magnitude and direction)? (10 pts) b) what is the net electric field at...
Problem 4 [25 pts] Grader & Score Consider two circular disks centered on the origin so...
Problem 4 [25 pts] Grader & Score Consider two circular disks centered on the origin so that when viewed from the side (i.e. the negative y-axis) they appear as bars in the diagram. Each disk has an area R2 and a positive charge Q. The disks are separated by a small distance s R so that the center of the top disk is located at<0,Q,s/2 > and the center of the bottom disk is at < 0,0, -s/2 >. Point...
Tutorial 4. Electric Potential and Electric Field. Circuits. Problem 1. The potential as a function of...
Tutorial 4. Electric Potential and Electric Field. Circuits. Problem 1. The potential as a function of coordinate x is shown in the figure. Potential Potential 0 10 15 x(cm) a) Show all points at which the electric field is zero. b) At which points is the magnitude of the electric field at maximum? c) At which intervals is the electric filed directed to the left? d) At which intervals is it directed to the right? e) Can this electric field...
How to solve Part 4c? Sketches of electric field lines and equipotentials Sketch and answer 4...
How to solve Part 4c?
Sketches of electric field lines and equipotentials Sketch and answer 4 - A through 4 - D in your answer book. Consider different charge configurations as shown: 4 - A : Suppose you are a test charge and you start at some distance from the charge q = +1 below, such as at the point X. Starting at point X, what path could you move along without doing any work? i.e. which Ē. ds is...
Problem (25 pts). Without doing any calculation, what is the value of the electric field at the origin O due to the configuration of 4 point charges shown in the Figure below? Justify your answer with 1 short sentence Bonus (Optional) Problem 5 (25 pts). The Figure below shows a thin nonconducting rod of length L-20 em A total charge of Q-8C is spread uniformly along it. What is the electric field vector at the point P which is located...
All charges are the same distance from the origin.
1) Without doing any calculations, does the electric field at
the origin in diagram 1 have a magnitude that is greater than, less
than, or equal to the magnitude of the field at the origin in
diagram 2? Justify.
2) If the distance between the charges and the origin is 6.1cm.
For each diagram shown, determine the magnitude and direction of
the electric field at the origin. (show calculations/equations)
ty ty...
Problem 1 (25 pts) A. [4 pts) A particle with charge q = -1.5 x 10-15 C creates an electric field Ē, at location A. What is the direction of E, at location A? Refer to the rosette in the figure and select a letter that corresponding to the best choice of direction. A B C D E F G H I A X I - zero magnitude B. (4 pts) Next a neutral metal block is placed in the...
Problem Solving What is the value of the electric field at Point A (halfway between the two positive charges) due to the given charge distribution? 6.00 c A 1.50pC -2.00 μ 3.00 cm2.00 cm Use the superposition principle- the Electric field as some distance r from a point charge Q is: 2
homework due soon !!
Question 2 25 pts A pair of point charges, 91 = +7.50 C and q2 = -5.00 uC are moving as shown below with speeds v1 = 9.50 x 104 m/s and V2 = 7.00 x 104 m/s. When the charges are at the locations shown in the figure a) what is the net magnetic field at the origin (magnitude and direction)? (10 pts) b) what is the net electric field at the origin (magnitude and...
homework due soon!!
part B & C please
Question 2 25 pts A pair of point charges, 91 = +7.50 C and q2 = -5.00 uC are moving as shown below with speeds v1 = 9.50 x 104 m/s and V2 = 7.00 x 104 m/s. When the charges are at the locations shown in the figure a) what is the net magnetic field at the origin (magnitude and direction)? (10 pts) b) what is the net electric field at...
Problem 4 [25 pts] Grader & Score Consider two circular disks centered on the origin so that when viewed from the side (i.e. the negative y-axis) they appear as bars in the diagram. Each disk has an area R2 and a positive charge Q. The disks are separated by a small distance s R so that the center of the top disk is located at<0,Q,s/2 > and the center of the bottom disk is at < 0,0, -s/2 >. Point...
Tutorial 4. Electric Potential and Electric Field. Circuits. Problem 1. The potential as a function of coordinate x is shown in the figure. Potential Potential 0 10 15 x(cm) a) Show all points at which the electric field is zero. b) At which points is the magnitude of the electric field at maximum? c) At which intervals is the electric filed directed to the left? d) At which intervals is it directed to the right? e) Can this electric field...
How to solve Part 4c?
Sketches of electric field lines and equipotentials Sketch and answer 4 - A through 4 - D in your answer book. Consider different charge configurations as shown: 4 - A : Suppose you are a test charge and you start at some distance from the charge q = +1 below, such as at the point X. Starting at point X, what path could you move along without doing any work? i.e. which Ē. ds is...
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