Assume that population means are to be estimated from the samples described. Use the sample results to approximate the margin of error and 95% confidence interval. Sample size equals =1, 043, sample mean equals =$46, 198, sample standard deviation equals = $26,000
Assume that population means are to be estimated from the samples described. Use the sample results...
Assume that population means are to be estimated from the sample described. Use the sample results to approximate the margin of error and 95% confidence interval. Sample size = 1030 Sample mean = $46,228 Sample Standard Deviation = $25,000 1) the margin of error is $ ? 2) find the 95% confidence interval ?
Assume that population means are to be estimated from the sample described. Use the sample results to approximate the margin of error and 95% confidence interval. Sample size = 1046 Sample mean = $46,223 Sample Standard Deviation = $28,000 1) The Margin off error is? 2) Find the 95% confidence interval? $. < < $.
Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of error and 95% confidence interval. Sample size, n= 100; sample mean, x = 74.00 cm; sample standard deviation, s=5.00 cm The margin of error is cm. (Round to two decimal places as needed.) Find the 95% confidence interval. cm<u< cm (Round to two decimal places as needed.)
o Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of error and 95% confidence interval n = 36. X = 62.8 seconds, S = 6.1 seconds The margin of error is seconds (Round to one decimal place as needed) Find the 95% confidence interval seconds <<seconds (Round to one decimal place as needed.) imeframe Enter your answer in each of the answer boxes This course (STATISTICAL REASONING IN...
Assume the population proportion is to be estimated from the sample described. Find the approximate margin of error and the 95% confidence interval for the population proportion. Sample sizeequals144, sample proportionequals0.28 The margin of error is nothing. (Round to four decimal places as needed.) Find the 95% confidence interval.
#3. 2 Consider the following results for two samples randomly taken from two populations. AWN Sample Size Sample Mean 7 Sample Standard Deviation Sample A Sample B 20 25 28 22 9 a. Determine the degrees of freedom for the t distribution. 10 b. At 95% confidence, what is the margin of error? 11 c. Develop a 95% confidence interval for the difference between the two population means.
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals$5, standard deviation equals$19 The required sample size is __.
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals=$66, standard deviation equals=$2222 The required sample size is _____. (Round up to the nearest whole number as needed.)
Consider random samples of size 265 drawn from population A with proportion 0.13 and random samples of size 285 drawn from population B with proportion 0.31. (a) Find the standard error of the distribution of differences in sample proportions, p A D B. Round your answer for the standard error to three decimal places. standard error Consider random samples of size 86 drawn from population A with proportion 0.44 and random samples of size 66 drawn from population B with...
1. Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (4.0, 4.8) when estimating the mean height (in centimeters) of a sample of seedlings. 2. In a random sample of 26 people, the mean commute time to work was 32.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval for the...