Question

Mr. Cooper is cruising along in the desert at 60 mph when he comes over a rise and sees a dappled fawn standing in the middle of the road. He quickly appraises the situation and hits the brakes 0.8 seconds later. He decelerates at a rate of 0.3 G (G is for gravity) and stops 1 yard in front of the still frozen in place fawn. How far from the fawn was Mr. Cooper when he first saw it? The equation for braking distance is d= Vt + (V^2/2a): where d is distance, V is speed, and a is acceleration. G=9.8 meters per second squared, 100 centimeters= 1 meter, 1 inch = 2.54 centimeters, 1 mile =5280ft, and 1 hr =60 minutes.

Answer 1