Question

Problem #3 Consider the pulley shown. Determine the velocity of block A assuming block B has a velocity Va when block B is located a distance y B from the top surface. YA ув [B

Answer 1

Sol) Finding the velocity of V_A

we have to find First find out the equation for Length, Change of length and Velocity.

So S_B= √ $d1YLwAAAABJRU5ErkJggg==$ (d/2)²+y _B ²---Equation (1)

SO L = Y_A +2 S _B

Substituting S_B value from equation (1)

SO, We get

L = Y_A +2√ $d1YLwAAAABJRU5ErkJggg==$ (d/2)²+y _B ²

Now, taking change of length

∆Y_A+2∆S_B=0

Here we are using displacement and velocity rule we, get

V_A+2 V_B=0---Equation(2)

Hence the velocity of Block A from equation (2) we can write as

VA=-2 VB

Hence, we got the velocity of block A