Question

2 CH,CHBr + 2 Me + C.HBOCH, OH C.H.CCHCH CH2CH3 109 g/mole 1.47 g/mL 24.3 g/mole 164 g/mole 136 g/mole 1.08 g/ml If 10.0 mL of bromoethane react with 5.0 g Mg, then with 10.0 g of methylbenzoate, and if 9.0 g of 3-phenylpentanol are formed, what is the percent yield? Show your work. 4. a) In the reductive amination reaction why is the NaBH, only added 15 minutes after the amine and the aldehyde have been mixed, and not right away? b) What is a rotary evaporator (Rotovap) used for? c) In the Williamson Ether Synthesis, why did we use a reflux assembly and not just boil the reactants in a beaker or flask? d) Would you expect the melting point of a crude product to be higher or lower than the melting point of a recrystallized product? Why?

Answer 1

2CH2CBY+ 2 Mg+ Cyt-0C>4- -S 243 136 099/md 1.0eg/mt J-43/m Mas oml omo EThane dxV -147g/miID ml CH CH ma - mg e Let us find imitng reagent CHC 2x19 C4H2r gives 1647 3Phenyffantand 2xlo9 2x L43M taming {64g 3-phankpertan 59 16-879 षा5 2x24-3 136 murh Re naoak gies 164 12.059 10 x l64/136 C2 faning lower yiald 3-phunpenans s s Br is limiting vagent and yisdd o9 Percent yid = al yid Thearelielyield 9«09