Question

он Cam BacHs CeHsCCH2CH СHCH IS 3. 2 CH CH Br+ 2 Mg+ 164 g/mole 136 g/mole 1.08 g/mL 109 g/mole 1.47 g/mL 24.3 g/mole If 10.0 mL of bromoethane react with 5.0 g Mg, then with 10.0 g of methylbenzoate, and if 9.0 g of 3-phenylpentanol are formed, what is the percent yield? Show your work HO Ho 4. a) In the reductive amination reaction why is the NABH4 only added 15 minutes after the amine and the aldehyde have been mixed, and not right away? + HAHO oOHRCH b) What is a rotary evaporator (Rotovap) used for? c) In the Williamson Ether Synthesis, why did we use a reflux assembly and not just boil the reactants in a beaker or flask?

Answer 1

Solution: + 109 9/md 11479m 243 136mel 1.0831mL 164 503 10.09 10ML Nat wayt of 100×47 ニ 14.7g moles 147 0.1348 m 109 5. 0 24.3 O2057mo metyl beageateo. Since mol methyl bengeate reguire to reauts oith moles 2 0.0735 m 136.6 2 mo 6romoethane and 2mdl Mg bremoethane reguired to reat Hence, amouut with o.0735 mel ofmetoyl begte - o0735×2 こ0.14470 mel Tea tout Heney metyltenzate is 73-phengl pentoncl fomedo.o 735 mo Treoretieal yieldel 3preypentoml Limidig Nout, mole .o735 X164 z Ro vield z Actual Vaield Y100 Thereticalyield 9.0 12.05 = 77%