Question

7. Calculate the homicide rate per 100,000 people for each state and province in 1997 and 2008. Which state and which province had relatively higher homicide rates each year? Which country seems to have the higher homicide rate? Write a couple o sentences describing your results. Table 2. Homicides and Population Counts for Select States/Provinces, 1997-2008 1997 2008 State/province New Jersey Iowa Alabama Texas California Nova Scotia Quebec Ontario Manitoba British Columbia Homicides Population HomicidesPopulation 338 52 426 1,327 2,579 24 132 178 31 116 8,053,000 2,852,000 4,139,000 19,439,00 32,268,000 936,100 7,323,600 11,387,400 1,137,900 3,997,100 376 76 353 1,374 2,142 12 92 176 54 8,883,000 3,003,000 4,882,000 24,327,000 36,757,000 936,600 7,753,000 12,936,300 1,206,000 4,383,800 Source: Census Bureau &Statistics Canada, reported in Healey, Prus, & Lieflander (2016)

Answer 1

	1997			2008
State/province	Homicides (H)	Population (P)	Homicide rate per 1000 poplation=H*1000/P	Homicides (H)	Population (P)	Homicide rate per 1000 poplation=H*1000/P	Rate difference=1997-2008
New Jersey	338	8053000	0.0420	376	8883000	0.0423	-0.0004
Iowa	52	2852000	0.0182	76	3003000	0.0253	-0.0071
Alabama	426	4139000	0.1029	353	4882000	0.0723	0.0306
Texas	1327	19439000	0.0683	1374	24327000	0.0565	0.0118
California	2579	32268000	0.0799	2142	36757000	0.0583	0.0216
Nova Scotia	24	936100	0.0256	12	936600	0.0128	0.0128
Quebec	132	7323600	0.0180	92	7753000	0.0119	0.0062
Ontario	178	11387400	0.0156	176	12936300	0.0136	0.0020
Manitoba	31	1137900	0.0272	54	1206000	0.0448	-0.0175
British Columbia	116	3997100	0.0290	117	4383800	0.0267	0.0023

From the homicide rate per 1000 population between the year 1997 and 2008, we can conclude that the homicide rates are decreasing at most of the states/ provinces except New Jersey, Iowa, and Manitoba.