Solve for the positive values of Y
a) .5Y=5,000-20r and Y=2000+10r.
b) Y=K1/3 K=(s/d+n)3/2 s=.5, d=.01, n=.04
c) dY/dK =2 Y=K1/2
Solve for the positive values of Y a) .5Y=5,000-20r and Y=2000+10r. b) Y=K1/3 K=(s/d+n)3/2 s=.5, d=.01,...
3. Solve the recursion equation: y[n] – 5y[n – 1] + 6y[n – 2] = 2 U[n] with y[-1] = 6 and y[-2] = 4
Feedback Control of Dynamic System Please Let me know how to solve this problem (5) For the following unity-feedback control system, Y(s) R(s)E D(s) (s+ 2) we want to design a controller D(s) D(s)+a) that makes the closed-loop stable for certain positive K values. Design the parameters a and b to satisfy the design condition through the root- locus method (5) For the following unity-feedback control system, Y(s) R(s)E D(s) (s+ 2) we want to design a controller D(s) D(s)+a)...
Please help me with these questions, show working. thank you I-(8z2+3e3rcos(5y) i-( 5e3rsin(5y)) j+16xz k The vector field I is conservative, find a scalar potential function f(x.y,z) such that I grad f and f(0,0,0) 1 Your answer should be expressed using the correct Maple syntax; for example, it might be: 2*x^2"y+5*z*exp(-9*y) cos(4*z) Do not use decimal approximations all numbers must be correct Maple expressions. The scalar potential is f(x,y,z) Skipped Change the order of integration and evaluate the following double...
Consider the initial value problem O if 0 t<3 y+5y={11 if 3 <5 if 5 t00, y(0) = 10 (a) Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y by Y. Do not move any terms from one side of the equation to the other (until you get to part (b) below). 11 A-3s)/5-11e-5s)/5+10 (S+5)Y (b) Solve your equation for Y Y =Lly) (c) Take...
SOLVE THE FOLLOWING SYSTEM OF EQUATIONS BY THE CRAMER'S METHOD 3X+5Y+3Z-12 2X+5Y-2Z-6 3x+6Y+3Z-3 a) X Y b) CHECK YOUR RESULTS. (USE MATRICE FUNCTIONS, PRESS F2. AND THEN PRESS CTRL+SHIFT+ENTER) 3IF Y-SINC) EXPOO. INTEGRATE Y FROM X-0 Tox-1. COMPARE WITH REAL VALUE IF DX-0 a) INT b) INT ,IF DX- 005 REAL VALUE 3) Plot sin x letting maco c/ Prepave hese cuves 4) SOLVE THE FOLLOWING SYSTEM OF EQUATIONS BY INVERSE METHOD 3 X+3Z-13 2X +5 Y-2Z-2 3 X+6Y+2Z-3 Z-...
2. Indicate a rectangle (that is, an interval of t-values and an interval of y-values) in which the requirements of the theorem on existence and uniqueness are satisfied for the non-linear initial value problem dy 1 sin(t)y(ty 2y +4t - 8) = 0 dt with the given initial condition. If no such rectangle exists, explain why not. Do NOT solve the equation y(5) 5 (b) (c) y(1)4 (a) y(0) 3 = = 2. Indicate a rectangle (that is, an interval...
With a per-worker production function y = k1/2, the steady-state capital stock per worker (k*) as a function of the saving rate (s) is given by: A) k* = (s/ )2. B) k* = (/s)2. C) k* = s/. D) k* = /s. Answer is A, I need to understand the process. Thanks We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this image
5. Consider the following. b. l-200+.5Y-750r C. G 450 d· T-100 e. (M/P)d-4y-5000 f. (m/p)- 2000 I Calculate IS curve function, LM curve function, equilibrium consumption, equilibrium investment and verify your values at the end. a. Y: b. R: c. C Il What would the effect of monetary expansion be on equilibrium output, interest rate, consumption, and investment if it took the form of a decrease in money supply to 1500? a. Y2: b. R2: c. C2 d. 12: lI...
Answer for the last box only please. Thanks Entered Answer Preview Result Y's+5°Y+2 Ys + 5Y +2 correct (5/s)*([e^(-s)]-1) correct (5*[e^(-s)]-5-2*s/[s*(s+5)] 5e : - 5 - 28 $(8 + 5) correct u(t-1)"[u(t-1)-(e^{-5* (t-1)]]]-u(t)+(e^(-5*t)]-(2/5) ult – 1)(ult – 1) – е11-1)) – u(t) +e5 incorrect At least one of the answers above is NOT correct. (1 point) In this exercise we will use the Laplace transform to solve the following initial value problem: 1 + 5y = -5, ( 0, 0<t<...
6) Consider a closed economy described by the following equations: (1) Y=C+I+G (2) Y = 5(K)S(L)05 (3) K = 1600 (4) L = 1600 (5) G = 2500 (6) T = 2000 (7) C = 1000 + 2/3 (Y-T) (8) I= 1200 - 100r, where r is the real interest rate. a) What is the equilibrium level of income? Show your work. b) Solve for the equilibrium interest rate (r) and the level of investment (I). The interest rate will...