Question

A 36.2-cm diameter disk rotates with a constant angular acceleration of 2.8 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time. (a) Find the angular speed of the wheel at t = 2.30 s. rad/s (b) Find the linear velocity and tangential acceleration of P at t = 2.30 s. linear velocity m/s tangential acceleration m/s2 c) Find the position of P (in degrees, with respect to the positive x-axis) at t = 2.30s.

Answer 1

twee wa? a = 2.5 red / 0 = 57.3 = 1:00 000zled rod rad = 18-1 con . = 18 - 1 1187 m. t-2.30 sec w = wo tat wzot (2.8) (2.3) w = 6-44 sad / At=2.30 sec rw v= - = = 18.1 x 102m x (6.44 rada) 1.16 mis - at=rd = 18. 1810-2m x (2-8 rad 1 82) 6.506 x 0-51 m/s² - c) L a t=2.3sec o = wot tat² wg=0 radle 0 = 1 +² =x (2.8) (2. 3² 7.406 pod 424.33 degrees 2 64 33° wataraxis

From , Pat too = 57.3° to P2.30 = 424.33 - Pront xtenso) = 481-63° Porta (2-30) = 121-63°