Question

A wheel 2.50 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 3.55 rad/s2


A wheel 2.50 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 3.55 rad/s2. The wheel starts at rest at t = 0, and the radius vector of a certain point P on the rim makes an angle of 57.3° with the horizontal at this time. At t = 2.00 s, find the following. 


(a) the angular speed of the wheel 7.1 rad/s 

(b) the tangential speed of the point P 

(c) the total acceleration of the point P 

(d) the angular position of the point P 

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Answer #1

your response of d is 8.1 rad. it is correct. but initial position was given in degrees. so 8.1 rad = 464.1 degree

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Answer #2

Part D is incorrect in Answer #1 because . . . . . 

One revolution in radians is roughly 

6.28  rad, so you will have to subtract 2π from your 8.1 radian displacement to represent point P's position on the circle. This will give you with a final answer of 1.817 rad.


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answered by: K
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