here,
the constant speed of student , u1 = 4.3 m/s
accelration , a2 = 0.95 m/s^2
t1 = 2 s
let the time taken to reach the bus be t and distance travelled be s
for bus
s = 0 + 0.5 * a2 * ( t1 + t)^2
s = 0 + 0.5 * 0.95 * (t + 2)^2 .....(1)
and
for student
s = u1 * t
s = 4.3 * t ....(2)
from (1) and (2)
s = 4.22 m
t = 0.98 s
the distance travelled is 4.22 m
and
time taken is 0.98 s
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