Question

The mean height of men is 69.7 inches. Assume that the heights of men are normally distributed, with a standard deviation of 2.9 in. a. [2 pts] 10% of men are taller than which height? Round your answer to 1 decimal place. b. [2 pts] Find the percentage of men that are 6'0" or taller. Round your final answer to 2 decimal places. c. [1 pts]How does the approximate percentage for the height of men 6'0" or taller (from the normal distribution) compare with the actual percentage of baseball players 6'0" or taller (from Problem 1? d. [1 pts]Based on your normal distribution calculation from part (b), approximately how many Major League Baseball players would you expect to be 6'0" or taller? Round your answer to the nearest whole number.

Answer 1

Given that

Mean Height of Men = 69.7

standard Deviation = 2.9

Let X be the random variable heights of men in inches

X ~ N (mean, variance)

X ~ N (69.7, 2.9²)

c) Appropriate percentage for the height of men 6'0" or percentage of baseball players 6'0" or taller

Unable to answer this part because we need the percentage from problem 1

d) Approximately how many major league baseball players would be expect to be 6'0" or taller

Let the total player in the league is "x"

Number of players taller than 6'0" = 0.21x