Question

use MATLAB and PLZ comment the code so that it is easy to understand

Implement the following series of sinusoidal signals in MATLAB: 1 sin(kt) where N 30 k=1 x(t) k 1 Write a MATLAB script which does the following steps First define and plot signal sin(t) for 0 St s 3Twhere T is the fundamental period of this signal The signal you just implemented is x(t) with N 1 a. Then modify your code to be able to define and plot signal sin(t) sin(2t) for 0 ts 37. The b. signal you just implemented is x(t) with N 2, Once you make sure your code works properly, implement x(t) with N 30. Use a "for loop" to C. see the effect of increasing N. Simply use "plot" define this signal. In each loop plot your signal to command without "hold on" to see one signal in your figure. Use "pause" command in each loop to slow down executing the code, so that you are able to see the changes in your figure for each value of N d. Do not forget to choose an appropriate Ts (sampling time) when you define your time axis implement sinusoids with high frequencies. Otherwise, you could not

Answer 1

(a) MATLAB CODE:

clc
clear all
close all

T = 2*pi;
t = 0:0.01:3*T;
x = sin(t);

plot(t,x)
xlabel('t')
xlim([0 3*T])
title('sin(t)')
grid on

OUTPUT:

sin(t) 0.8 0.6 0.4 0.2 0 -0.2 -0.4 0.6 -0.8 10 6 8 12 14 16 18
(b) MATLAB CODE:

clc
clear all
close all

T = 2*pi;   % Fundemental period
t = 0:0.01:3*T;
x = sin(t) + (1/2)*sin(2*t); % x(t) when N = 2

plot(t,x)
xlabel('t')
xlim([0 3*T])
title('sin(t) + (1/2)*sin(2t)')
grid on

OUTPUT:

sin(t)(1/2)sin(2t) 1.5 0.5 0 0.5 -1 1.5 6 8 10 12 14 16 18

(c) MATLAB CODE:

clc
clear all
close all

T = 2*pi;   % Fundemental period
t = 0:0.01:3*T;

N = 1:30;
for i = 1:30;
   
    x = 0;
   for k = 1:N(i);
       x1 = (1./k).*sin(k.*t);
       x = x + x1;
      
       plot(t,x)
       xlabel('t')
      
       pause(2) % Stops execution for 2 seconds
   end
end