5.
Yeild to maturity of consol = 85 / 1000 = 0.085 = 8.5%
Option B is correct
6.
Loan amount = 23000, tenure = 120 monthly payments, monthly payments = 226.36
let monthly yeild to maturity be i, then
23000 = 226.36 * ( P/A, i%, 120)
( P/A, i%, 120) = 23000 / 226.36 = 101.6081
using trail and error method
when i = 0.25% , value of ( P/A, i%, 120) = 103.5618
when i = 0.5% , value of ( P/A, i%, 120) = 90.07345
Using interpolation
i = 0.25% + (103.5618 - 101.6081) / (103.5618 - 90.07345) * (0.5% - 0.25%)
i = 0.25% + 0.03621%
i = 0.2862%
Yeild to maturity = (1+0.002862)^12 -1 = 1.0348911 - 1 = 0.0348911 = 3.48%
Option B is correct, minor diff due to hand calculations and in between steps being decimal calculations
7
P = F / (1+i)^t
Loan amount = 1400, payment per year for three years = 500
Let yeild to maturity be i
Then,
1400 = 500/(1+i) + 500/(1+i)^2 + 500/(1+i)^3
Option C is correct
8.
if market interest falls, then the market price of bonds increase
So option B is correct
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