Question

please advise if calculations are correct. i got confused on the signs when i got to 4 and for hess's law i plugged in the equations given to me in the lab for the experiments and the delta H from the above part 1 calculations. based on the directions i only added up the last two. could you help bring this to light?

thank you

AHCI M Trial 2 075 Enthalpy of Solution Write the balanced reaction for HJ C dissolving NH4Cl (s) here: NHA In the space below this table, show the calculations for numbers 2, 3, and 4 for Trial 1. Trial 1 1. Mass of NH4Cl (1) used 4,01aa 2. moles of NH4CI () used 3. AT (from graph) +27 4. heat absorbed or evolved by the neutralization reaction (-qcal) -11 9408 S 5. AH solo per mole of NH4CI () used expressed in kJ/mole NH4C1 -15 0024 Kima 6. average Hvoln expressed in WJ/mole NH4CI M: Mol (MCL)- mores cism, cS)--075moles .075L - X 5349Why CL- 3 21.90-19,2=+27] 4.olag 4 -9 = -(100) (4.184J/g) (+2) - 1129.685 - 1129.683 Hess's Law Calculation Dola 4S/mole = -15.0624 To the following reactions add the two reactions you studied in the lab (make sure you write them in the correct direction and use the appropriate sign for the average heats calculated) in order to get the desired formation reaction for NH4Cl (s)- 1/2 N20 + 3/2 H2 (6) NH3 () 1/2 H26) + 1/2 Ch (8) ► HCI) NH3 + NH3 (aq. 1.50 M) HCIO) → HCI (aq, 1.50 M) NHolagir HelH +C1 (neut, nxn part) NHCl Hy ter (soln. rxn part) |À N aCl -- NH Cô (ormation an) AH® rx = -45.77 kJ AHørx = -92.31 kJ AH® rxn=-35.40 kJ AH® rxn=- 72.84 kJ AH = 5740 AH = -15,06 kJ AH = 25

Answer 1

THIS IS CORRECT CALCULATION MATE as u have clearly write reaction in correct direction and sign conventions are also precise.