Question

How many milliliters of 0.130 M HCl are needed to completely neutralize 46.0 mL of 0.105 M Ba(OH)2 solution?

Express the volume in milliliters to three significant digits.

Answer 1

Cone of the = 0.130m = 0.130 mol/L lone of Balom, = 0.105 m = 0.105 mol/L Volume of Bar = 46.0 mL = 0.046 L no. of moo of Ba(OH)₂ = 0.105 mol/Lx 0.046 = 4.832 10 mod. ZHLO + Ba(OH) ballz +2420 I mod Balohi, neutralize by a mod He, then 4.83x10 mod Balon neutralize by 2x 4.83 10 = 9.66x10 mol Нte. Henie, no. of meo of re = 9.66 x 103 mol Volume of the = n 9. 66x15 mol 0.130 mos -3 Conen = 0.0743 L = 74.3 mL Menie 74.3mL of 0.130 me are needed to completel neuhalize 46.0mL of 0.105m Balon, saletion.