Question

- O ENTROPY AND FREE ENERGY Calculating dg from dH and ds A chemical engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 131.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. AN -76. U A8 = -238. x 5 ? 2NOG) + C, 6) - 2NOCIG) AG - IN Which is spontaneous? the reverse reaction neither AR70 kJ As=0 TIO, 6.) + 4HCG) -- TIC,G) + 2H,06) AG=0 Which is spontaneous? this reaction the reverse reaction O neither

Answer 1

T = 131€ = 13106+ 273 =5040k I reaction ignon tve spontanean 2 NOG) + dag - 2 Noel Q AH = -76 kJ = 76,000 57-re DS= - 230 J/K ove DG = ? = 43 kJ +ve DG =DH - TAS = - 76000 J - (50LkX- 230 J/K ) = -76000 J + 118,944 J = + 429 4 4 J - 43 KJ I - ( os Lo & DGSO, for world reaction is - non spontaneus. Answer, reverse reaction is spontanoous T10,0) + 4Hele Tic149) +2H200 RO OG = AH – TOS AH = 70 kJ 0 = AH-TAS = 70,00oJ ott 70,000 J 504ok = 130.09 J og = +1395 AG=0 reaction is at equilibrium which is spontaneous Answer - niether